Pipe a can fill a tank in 5 hours pipe b can
Webb5 dec. 2024 · part of tank filled by pipe A = t/15 th part of tank filled by pipe B = t−3/15 th and, part of tank emptied by pipe C = t−4/15 th Therefore t 15 + t−3 12 − t−4 20 = 1 t 15 + t − 3 12 − t − 4 20 = 1 ⇒ t = 10.5 Total time to fill the tank = 10 hours 30 minutes OR 6 am, pipe C is opened to empty 1/2 filled tank Time to empty = 10 hours Webb13 juli 2024 · Pipe B can fill the tank = 6 hrs Formula used Work = Time × Efficiency Calculation LCM of (6, 8) = 24 Let the total capacity of tank be 24 Efficiency of A = 24/8 = 3/hrs Efficiency of B = 24/6 = 4/hrs A and B can fill the tank in 2 hrs = 7 × 2 = 14 Remaining tank can be fill by B in = (24 - 14)/4 = 2.5 hrs
Pipe a can fill a tank in 5 hours pipe b can
Did you know?
Webb24 maj 2024 · A + B in 5 minutes = [1/12 + 1/15]×5 = ¾ ⇒ 3/4 th part of tank is filled in 5 minutes. When C is also opened, work done by all pipes in 1 minute = 1/12 + 1/15 – 1/6 = 1/60 When all three are opened, the tank is emptied in 60 minutes. So, 3/4 part will be emptied in = 60 x 3/4 = 45 minutes Q7. WebbSolution Verified by Toppr Tap A can fill 1 tank in 8 hours Tap A fills in 1 hour = 81tank Tap B can empty 1 tank in 12 hours. Tap B empties in 1 hour= 121 tank Both taps will fill in 1 hour = ( 81− 121) tank = 243−2 = 241 Hence, the tank will be filled completely in 24 hours Was this answer helpful? 0 0 Similar questions
Webb12 feb. 2024 · Pipe A can fill a tank in 90 minutes. Pipe B whose diameter is 3 times that of Pipe A also fills the tank. lf both the pipes are kept open when the tank is empty, how … Webb7 mars 2024 · Let the capacity of tank be LCM (10, 12, 30) = 60 units => Efficiency of pipe A = 60 / 10 = 6 units / hour => Efficiency of pipe B = 60 / 12 = 5 units / hour => Efficiency of pipe C = – 60 / 30 = – 2 units / hour (Here, ‘-‘ represents outlet pipe) => Combined efficiency of pipes A, B and C = 6 + 5 – 2 = 9 units / hour Therefore, time taken to …
WebbTwo pipes can fill a tank in 20 minutes and 30 minutes respectively. If both the pipes are opened simultaneously, then the tank will be filled in Easy View solution > View more Get the Free Answr app Click a picture with our app and get instant verified solutions Scan Me OR Receive an SMS with download link send WebbPipe A can fill a cistern in 6 hours and pipe B can fill it in 8 hours. Both the pipes are opened and after two hours, pipe A is closed. How much time will B take to fill the …
Webb3 okt. 2024 · A sink can be filled by a pipe in 5 minutes, but it takes 7 minutes to drain a full sink. If both the pipe and the drain are open, how long will it take to fill the sink? Solution We use the work-rate equation to model the problem, but before doing this, we can display the information on a table: Now, let’s set up the equation and solve.
Webb★★ Tamang sagot sa tanong: 4. Pipes A and B can fill the pool in 10 hours. Pipe A can fill the tank in 3x hours while pipe Bcan fill it in x hours. How long can pipe B fill the tank … songs you play at a funeralWebb24 jan. 2024 · Work done per hour by Raman = 1/12. Work done per hour by Ravi and Raman together = 1/15 + 1/12. = 9/60. = 3/20. ∴ Time taken by Ravi and Raman together to finish the work = 20/3 hours. Question 3: A and B, working together can finish a piece of work in 6 days, while A alone can do it in 9 days. small green lizard with red throatWebb15 apr. 2024 · Pipe A and Pipe B can fill the water tank in 10 hours and 12 hours. After some time Pipe B is closed and the water tank is filled within 5 hours. Calculate how many hours, we need to close Pipe B to fill the water tank? Solution: As per the given details, Pipe A can fill the water tank = a = 10 hours. Pipe b can fill the water tank = b = 12 hours. small green melon with green flesh